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Question Number 207487 by hardmath last updated on 17/May/24

∣x^2 − 3x − 4∣ = ∣x − 4∣ find: min and max = ?

∣x2−3x−4∣=∣x−4∣find:minandmax=?

Answered by A5T last updated on 17/May/24

∣x−4∣∣x+1∣=∣x−4∣⇒∣x−4∣=0 or ∣x+1∣=1 ⇒x−4=0 or x+1=1 or x+1=−1 ⇒x=4 or 0 or −2⇒ min=−2; max=4

∣x−4∣∣x+1∣=∣x−4∣⇒∣x−4∣=0or∣x+1∣=1⇒x−4=0orx+1=1orx+1=−1⇒x=4or0or−2⇒min=−2;max=4

Commented by hardmath last updated on 17/May/24

thank you professor

thankyouprofessor

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