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Question Number 207498 by hardmath last updated on 17/May/24

cos2x + sinx = tg(225°)∙(0,360°)  sum of roots = ?

cos2x+sinx=tg(225°)(0,360°)sumofroots=?

Answered by MM42 last updated on 17/May/24

−2sin^2 x+sinx=0  sinx=0⇒x=π  sinx=(1/2)⇒x=(π/2)  ⇒s=((3π)/2) ✓

2sin2x+sinx=0sinx=0x=πsinx=12x=π2s=3π2

Commented by hardmath last updated on 17/May/24

thank you professor

thankyouprofessor

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