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Question Number 207610 by Davidtim last updated on 20/May/24

$$wehave100moneyifwewanttobuy100DonkysHorses$$$$andCamelsmixedwhile20Donkys$$$$cost1money,1Horsecosts1moneyand$$$$1Camelcosts5money.$$$$findtotalnumberofDonkys,Horses,$$$$andCamels.$$

Commented by Davidtim last updated on 21/May/24

$$pleasehelpme!!!$$

Answered by Tinku Tara last updated on 21/May/24

$$\mathrm{If}\mathrm{we}\mathrm{buy}d\mathrm{donkeys},h\mathrm{horses}\mathrm{and}$$$$c\mathrm{camels}.$$$$\mathrm{c}+\mathrm{h}+\mathrm{d}=100\left(\mathrm{i}\right)$$$$\mathrm{money}\mathrm{for}\mathrm{camels}5\mathrm{c},\mathrm{horses}h,$$$$\mathrm{and}\mathrm{donkeys}\mathrm{d}/20$$$$5\mathrm{c}+\mathrm{h}+\frac{\mathrm{d}}{20}=100\left(\mathrm{ii}\right)$$$$\left(\mathrm{ii}\right)-\left(\mathrm{i}\right)$$$$4\mathrm{c}-\frac{19\mathrm{d}}{20}=0$$$$19\mathrm{d}=80\mathrm{c}$$$$\mathrm{d},\mathrm{c}\mathrm{are}\mathrm{integers}\mathrm{so}\mathrm{only}\mathrm{solution}\mathrm{is}$$$$\mathrm{c}=19$$$$\mathrm{d}=80$$$$\mathrm{c}+\mathrm{d}+\mathrm{h}=100$$$$\Rightarrow \mathrm{h}=1$$$$\mathrm{C}amels19$$$$\mathrm{Donkeys}80$$$$\mathrm{Horses}1$$

Commented by Davidtim last updated on 21/May/24

$$somuchthanks$$

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