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Question Number 207639 by hardmath last updated on 21/May/24

Commented by Berbere last updated on 21/May/24

$$falsenottrue$$$$\left(\begin{array}{c}2n\\ n\end{array}\right)\sim \frac{4^n}{\sqrt{\pi n}}$$$$\frac{2^{-2(n-1)}(n+1)(n+3)}{(n+2)(n+4)}{\left(\begin{array}{c}n\\ 2n\end{array}\right)}^2\sim \frac{4^n}{\pi n}diverge$$

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