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Question Number 207801 by naka3546 last updated on 27/May/24

lim_(t→∞)   ∫_0 ^(      π)   ((sin (tx))/x) dx  = ∙∙∙

limtπ0sin(tx)xdx=

Commented by naka3546 last updated on 27/May/24

t →∞

t

Answered by Frix last updated on 27/May/24

∫_0 ^π ((sin tx)/x)dx=Si πt  lim_(n→∞)  Si n =(π/2)

π0sintxxdx=SiπtlimnSin=π2

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