Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 207885 by hardmath last updated on 29/May/24

Find:  i^4  + i^8  + i^(12)  + i^(16)  + i^(20)  + i^(24)  +...+ i^(100)  = ?

Find:i4+i8+i12+i16+i20+i24+...+i100=?

Commented by mr W last updated on 29/May/24

do you mean i=(√(−1)) ?

doyoumeani=1?

Commented by hardmath last updated on 29/May/24

yes professor...  answer: 25

yesprofessor...answer:25

Commented by mr W last updated on 29/May/24

i^4 =i^8 =i^(16) =...=i^(100) =1  Σ=1+1+1+...+1_(25 times) =25

i4=i8=i16=...=i100=1Σ=1+1+1+...+125times=25

Commented by hardmath last updated on 29/May/24

  Professor, is there a golden rule for these types of examples?

Professor, is there a golden rule for these types of examples?

Commented by mr W last updated on 29/May/24

i=(√(−1))  i^2 =−1  i^4 =(−1)^2 =1  i^8 =i^4 ×i^4 =1×1=1  ...

i=1i2=1i4=(1)2=1i8=i4×i4=1×1=1...

Commented by hardmath last updated on 29/May/24

thank you dear professor

thankyoudearprofessor

Commented by Frix last updated on 29/May/24

i^(4n) =1  i^(4n+1) =i  i^(4n+2) =−1  i^(4n+3) =−i

i4n=1i4n+1=ii4n+2=1i4n+3=i

Terms of Service

Privacy Policy

Contact: info@tinkutara.com