Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 207984 by Thomaseinstein last updated on 02/Jun/24

Answered by Frix last updated on 02/Jun/24

p, q >0 (1/p^2 )−(1/q^2 )=(4/3) ⇒ q^2 =((3p^2 )/( 3−4p^2 )) p+q=6 ⇒ q^2 =(p−6)^2 ((3p^2 )/( 3−4p^2 ))=(p−6)^2 p^4 −12p^3 +36p^2 +9p−27=0 p≈.854016106031 ⇒ q≈5.14598389396 ⇒ m≈.729343509360 n≈26.4811502370

p,q>01p2−1q2=43⇒q2=3p23−4p2p+q=6⇒q2=(p−6)23p23−4p2=(p−6)2p4−12p3+36p2+9p−27=0p≈.854016106031⇒q≈5.14598389396⇒m≈.729343509360n≈26.4811502370

Terms of Service

Privacy Policy

Contact: info@tinkutara.com