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Question Number 208011 by necx122 last updated on 02/Jun/24

Commented by necx122 last updated on 02/Jun/24

$I f t h e r a t i o o f < A R S : < B R T = 9 : 4,$ $f i n d t h e r a t i o o f a r e a A B C : a r e a A R S$
Commented by A5T last updated on 02/Jun/24

$N o t u n i q u e .$
Commented by A5T last updated on 02/Jun/24

Commented by A5T last updated on 02/Jun/24

$D o y o u m e a n a n g l e ∠ ? o r a r e a ?$
Commented by mr W last updated on 02/Jun/24

$q u e a t i o n i s b a d l y w r i t t e n . i t h i n k$ $h e m e a n s t h e r a t i o o f a r e a s, n o t t h e$ $r a t i o o f a n g l e s .$
Commented by necx122 last updated on 03/Jun/24

$u n f o r t u n a t e l y I d i d n t m a k e a m i s t a k e .$ $B a s e d o n m y r e f e r e n c e t e x t t h e y w r o t e$ $t h e s y m b o l f o r a n g l e a n d n o t a r e a . I c a n$ $s e e n o w t h a t t h e i s s u e c a m e f r o m t h e$ $t e x t b o o k . T h a n k s$
	Answered by mr W last updated on 02/Jun/24

	Commented by mr W last updated on 02/Jun/24

	$\frac{Δ A R S}{Δ B R T} = \frac{9}{4} = {(\frac{a}{b})}^{2} \Rightarrow \frac{a}{b} = \frac{3}{2}$ $\frac{Δ A B C}{Δ A R S} = {(\frac{b + a}{a})}^{2} = {(1 + \frac{b}{a})}^{2} = {(1 + \frac{2}{3})}^{2} = \frac{25}{9}$
	Commented by necx122 last updated on 02/Jun/24

	$T h i s i s w o n d e r f u l f o r r e a l .$
	Commented by Tawa11 last updated on 21/Jun/24

	$Weldone sir$
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