we have y=f(x) function, if we transfer its graph C unit vertically and gain the new function y=f(x)±C, it′s meant y is increased or decreased C units. if we transfer the graph of considered function horizontally, we gain the new function y=f(x±C), what does mean it?


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Question Number 208031 by Davidtim last updated on 02/Jun/24

$w e h a v e y = f (x) f u n c t i o n, i f w e t r a n s f e r$ $i t s g r a p h C u n i t v e r t i c a l l y a n d g a i n$ $t h e n e w f u n c t i o n y = f (x) \pm C, {i t}^{'} s m e a n t$ $y i s i n c r e a s e d o r d e c r e a s e d C u n i t s .$ $i f w e t r a n s f e r t h e g r a p h o f c o n s i d e r e d$ $f u n c t i o n h o r i z o n t a l l y, w e g a i n t h e n e w f u n c t i o n$ $y = f (x \pm C), w h a t d o e s m e a n i t ?$
	Answered by Frix last updated on 03/Jun/24

	$y = f (x); C > 0$ $y + C = f (x) shifts down$ $y - C = f (x) shifts up$ $y = f (x + C) shifts left$ $y = f (x - C) shifts right$
	Commented by Davidtim last updated on 03/Jun/24

	$I k n o w i t b u t y o u r e a d m y q u e s t i o n a g a i n .$
	Commented by Frix last updated on 03/Jun/24

	$Ok, I read it again . What now ? {Where}^{'} s$ $the point ?$
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