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Question Number 208049 by mr W last updated on 03/Jun/24

Commented by Frix last updated on 03/Jun/24

a=1∧b=3 r=a+b−(√(a^2 +b^2 ))=4−(√(10))

a=1∧b=3r=a+b−a2+b2=4−10

Answered by mr W last updated on 03/Jun/24

Commented by mr W last updated on 03/Jun/24

AB=c=(√(a^2 +b^2 )) R=(c/2)=((√(a^2 +b^2 ))/2) (r−(a/2))^2 +(r−(b/2))^2 =(R−r)^2 r−(a+b−2R)=0 ⇒r=a+b−(√(a^2 +b^2 ))

AB=c=a2+b2R=c2=a2+b22(r−a2)2+(r−b2)2=(R−r)2r−(a+b−2R)=0⇒r=a+b−a2+b2

Commented by Tawa11 last updated on 21/Jun/24

weldone sir

weldonesir

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