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Question Number 208139 by efronzo1 last updated on 06/Jun/24

Answered by Ghisom last updated on 06/Jun/24

$$x>0$$$$\frac{\ln (x^2+1)+\ln x}{\ln 5+\ln 2}=\frac{\ln x}{\ln 2}$$$$\frac{\ln (x^2+1)}{\ln x}=\frac{\ln 5}{\ln 2}$$$$\mathrm{obviously}x=2$$

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