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Question Number 208148 by Blackpanther last updated on 06/Jun/24

Answered by A5T last updated on 06/Jun/24

Commented by A5T last updated on 06/Jun/24

$$2y=6x\Rightarrow y=3x$$$$\Rightarrow {15}^2={\left(3y\right)}^2+y^2=10y^2\Rightarrow y^2=\frac{225}{10}=\frac{45}{2}$$$$\Rightarrow \left[Bluesquare\right]={\left(2y\right)}^2=4y^2=4\times \frac{45}{2}=90$$

Answered by mr W last updated on 06/Jun/24

Commented by mr W last updated on 06/Jun/24

$$\frac{15}{a}=\frac{5}{\sqrt{5^2-a^2}}\Rightarrow a^2=\frac{45}{2}$$$$coloredarea={\left(2a\right)}^2=4\times \frac{45}{2}=90$$

Commented by Tawa11 last updated on 21/Jun/24

$$\mathrm{learning}\mathrm{sir}$$

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