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Question Number 208322 by alcohol last updated on 11/Jun/24
Answered by Berbere last updated on 11/Jun/24
∏n−1k=1(1+1k)k=∏n−1k=1(1+k)kkk=∏n−1k=1(1+k)k+1(k+1).kk=∏n−1k=11(k+1).∏n−1k=1(1+k)k+1kk=1n!.nn=nn−1(n−1)!
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