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Question Number 208377 by hardmath last updated on 14/Jun/24

sin x − sin (π/6) > 0  x = ?

sinxsinπ6>0x=?

Commented by hardmath last updated on 14/Jun/24

  Solve the inequality

Solve the inequality

Answered by lepuissantcedricjunior last updated on 14/Jun/24

x est definie dans quoi!  R ou ]−2𝛑;2𝛑]

xestdefiniedansquoi!Rou]2π;2π]

Answered by mr W last updated on 14/Jun/24

sin x > sin (π/6)  ⇒2kπ+(π/6)<x<(2k+1)π−(π/6)

sinx>sinπ62kπ+π6<x<(2k+1)ππ6

Commented by hardmath last updated on 14/Jun/24

thankyou dear professor  (π/6) +2πk   and   ((5π)/6) + 2πk ?

thankyoudearprofessorπ6+2πkand5π6+2πk?

Commented by mr W last updated on 14/Jun/24

is this not the same as i said?  ((5π)/6)=π−(π/6) !

isthisnotthesameasisaid?5π6=ππ6!

Commented by hardmath last updated on 14/Jun/24

Dear professor,  k = 0 ⇒ π − (π/6) = ((5π)/6) ?

Dearprofessor,k=0ππ6=5π6?

Commented by mr W last updated on 14/Jun/24

yes

yes

Commented by hardmath last updated on 14/Jun/24

thankyou dear professor

thankyoudearprofessor

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