a_1 >a_2 >a_3 >...>a_n >0 b_1 >b_2 >b_3 >...>b_n >0 prove Σ_(i=1) ^n a_i b_i ≥Σ_(i=1) ^n a_i b


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Question Number 208440 by liuxinnan last updated on 16/Jun/24

$a_{1} > a_{2} > a_{3} > . . . > a_{n} > 0$ $b_{1} > b_{2} > b_{3} > . . . > b_{n} > 0$ $p r o v e$ $\underset{i = 1}{\sum^{n}} a_{i} b_{i} ⩾ \underset{i = 1}{\sum^{n}} a_{i} b_{n - i + 1}$
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