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Question Number 208463 by hardmath last updated on 16/Jun/24

$$\mathrm{Compare}\mathrm{it}:$$$$\mathrm{a}={\log }_{3}4$$$$\mathrm{b}={\log }_{5}6$$$$\mathrm{c}={\log }_{6}2$$

Answered by Frix last updated on 16/Jun/24

$$3^a=4\Rightarrow a>13^a=3+1$$$$\Rightarrow a>b$$$$5^b=6\Rightarrow b>15^b=5+1$$$$$$$$6^c=2\Rightarrow c<1$$$$$$$$\Rightarrow a>b>c$$

Commented by hardmath last updated on 16/Jun/24

$$\mathrm{thankyou}\mathrm{dear}\mathrm{professor}$$

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