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Question Number 208623 by MWSuSon last updated on 19/Jun/24
solveforx,3x−2x=65
Answered by Berbere last updated on 19/Jun/24
ifx<03x<1&2x<1⇒3x−2x<1nosolutionifx⩾0x→f(x)3x−2x⇒f′(x)=ln(3)3x−ln(2)2x3x>2x;ln(3)>ln(2)⇒3xln(3)−2xln(2)=f′(x)>0f(4)=81−16=65⇒3x−2x=65hasuniquesolutionx=4
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