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Question Number 208646 by hardmath last updated on 20/Jun/24
y=∣x−2∣+∣x+4∣Find:min(y)andmax(y)
Answered by A5T last updated on 20/Jun/24
yhasnoglobalmaximum,y→+∞asx→+−∞∣x−2∣+∣−4−x∣⩾∣x−2−4−x∣=6⇒min(y)=6
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