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Question Number 208647 by hardmath last updated on 20/Jun/24

$$({\tan }^2\mathbf{x}-3)\cdot \sin \mathbf{x}=0$$$$\mathrm{Find}:\mathbf{x}=?$$

Answered by Frix last updated on 20/Jun/24

$$f\left(x\right)\times g\left(x\right)=0\iff f\left(x\right)=0\vee g\left(x\right)=0$$$$\sin x=0\Rightarrow x=n\pi$$$$\tan x=\pm \sqrt{3}\Rightarrow x=\pm \frac{\pi }{3}+n\pi$$

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