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Question Number 208661 by efronzo1 last updated on 20/Jun/24

$$\downharpoonleft \underset{―}{}$$

Answered by Berbere last updated on 20/Jun/24

$$3x+4=u\Rightarrow dx=\frac{du}{3}$$$${\int }_{10}^{25}f\left(u\right).\frac{du}{3}=\frac{1}{3}\{.{\int }_{10}^{15}f\left(u\right)du+{\int }_{15}^{20}f\left(u\right)du+{\int }_{20}^{25}f\left(u\right)du\}$$$$={\int }_2^{7}f\left(u\right)du=5$$

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