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Question Number 208670 by hardmath last updated on 20/Jun/24
Find:∫0512(x2−2x+1)dx=?
Commented by essaad last updated on 20/Jun/24
Answered by Berbere last updated on 20/Jun/24
x2−2x+1=(x−1)2...x2={x;x⩾0−x⩽0
Answered by mathzup last updated on 21/Jun/24
I=12∫05(x−1)2dx=12∫05∣x−1∣dx=12∫01(1−x)dx+12∫15(x−1)dx=12[x−x22]01+12[x22−x]15=12×12+12{252−5−(12−1)}=122+12(152+12)=122+82=12(8+12)=1722
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