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Question Number 208772 by Jubr last updated on 22/Jun/24

Answered by mr W last updated on 22/Jun/24

Commented by mr W last updated on 22/Jun/24

$${(r-a)}^2+{(r-\frac{a}{2})}^2=r^2$$$$4r^2-12ar+5a^2=0$$$$a=\frac{2r}{5}=\frac{2\times 5}{5}=2$$$$areaofsquare=a^2=2^2=4$$

Commented by Tawa11 last updated on 22/Jun/24

$$\mathrm{Thanks}\mathrm{sir}.$$$$\mathrm{I}\mathrm{really}\mathrm{appreciate}\mathrm{sir}.$$

Commented by Wuji last updated on 23/Jun/24

$$\mathbf{sir},\mathbf{what}\mathbf{app}\mathbf{do}\mathbf{you}\mathbf{use}\mathbf{for}\mathbf{the}\mathbf{duagrams}?$$

Commented by mr W last updated on 23/Jun/24

$$PhotoEditor$$

Answered by cherokeesay last updated on 22/Jun/24

Commented by Tawa11 last updated on 22/Jun/24

$$\mathrm{Thanks}\mathrm{sir},\mathrm{I}\mathrm{really}\mathrm{appreciate}\mathrm{sir}.$$

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