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Question Number 208915 by Tawa11 last updated on 27/Jun/24

Answered by mr W last updated on 27/Jun/24

Commented by mr W last updated on 27/Jun/24

$${BC}^2=a^2+b^2$$$$2R=\frac{BC}{\sin 45°}=\sqrt{2(a^2+b^2)}$$$$\Rightarrow a^2+b^2=2R^2$$$$bluearea=\frac{\pi (a^2+b^2)}{4}=\frac{\pi R^2}{2}$$$$=\frac{areaofredcircle}{2}=\frac{4\pi }{2}=2\pi$$

Commented by Tawa11 last updated on 27/Jun/24

$$\mathrm{Thanks}\mathrm{sir}.$$$$\mathrm{I}\mathrm{appreciate}\mathrm{sir}.$$

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