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Question Number 208999 by Spillover last updated on 30/Jun/24

Answered by mr W last updated on 30/Jun/24

Commented by mr W last updated on 30/Jun/24

F=mg−B  m=Vρ_(Iron)  ⇒V=(m/ρ_(Iron) )  B=((Vρ_(Oil) g)/2)=((mρ_(Oil) g)/(2ρ_(Iron) ))  ⇒F=(1−(ρ_(Oil) /(2ρ_(Iron) )))mg          =(1−((0.9)/(2×7.8)))×0.36×10=3.39N

F=mgBm=VρIronV=mρIronB=VρOilg2=mρOilg2ρIronF=(1ρOil2ρIron)mg=(10.92×7.8)×0.36×10=3.39N

Commented by Spillover last updated on 30/Jun/24

nice solution.thank you

nicesolution.thankyou

Answered by Spillover last updated on 30/Jun/24

Answered by Spillover last updated on 30/Jun/24

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