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Question Number 209062 by hardmath last updated on 01/Jul/24

Answered by som(math1967) last updated on 01/Jul/24

x^y^z =1 x,y,z ∈N ⇒1^y^z =1 ⇒x=1 y^z^x =125⇒y^z =5^3 ⇒y=5⇒z=3 z^y^x =3^5^1 =243 9x+10y−18z=9+10×5−18×3 =5

xyz=1x,y,z∈N⇒1yz=1⇒x=1yzx=125⇒yz=53⇒y=5⇒z=3zyx=351=2439x+10y−18z=9+10×5−18×3=5

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