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Question Number 209166 by Tawa11 last updated on 02/Jul/24

Answered by mr W last updated on 02/Jul/24

$$\left(a\right)$$$$p={\left(\frac{3}{4}\right)}^3=0.42$$$$\left(b\right)$$$$p=C_2^3{\left(\frac{1}{4}\right)}^2\left(\frac{3}{4}\right)=0.15$$

Commented by Tawa11 last updated on 02/Jul/24

$$\mathrm{Thanks}\mathrm{sir}.$$

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