If a, b, c are real numbers and z is a complex number such that, a^2 + b^2 + c^2 = 1 and b + ic = (1 + a)z, then ((1 + iz)/(1 − iz)) equals. (1) ((b − ic)/(1 − ia)) (2) ((a + ib)/(1 + c)) (3) ((1 − c)/(a − ib)) (4) ((1 + a)/(b + ic))


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Question Number 20932 by Tinkutara last updated on 08/Sep/17

$If a, b, c are real numbers and z is a$ $complex number such that, a^{2} + b^{2} + c^{2}$ $= 1 and b + i c = (1 + a) z, then \frac{1 + i z}{1 - i z}$ $equals .$ $(1) \frac{b - i c}{1 - i a}$ $(2) \frac{a + i b}{1 + c}$ $(3) \frac{1 - c}{a - i b}$ $(4) \frac{1 + a}{b + i c}$
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