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Question Number 209602 by peter frank last updated on 16/Jul/24

Answered by som(math1967) last updated on 16/Jul/24

 let number=x   ((120x)/(100)) −((85x)/(100))=14   ((35x)/(100))=14  ⇒x=((14×100)/(35))=40

letnumber=x120x10085x100=1435x100=14x=14×10035=40

Commented by peter frank last updated on 18/Jul/24

thank you

thankyou

Answered by som(math1967) last updated on 16/Jul/24

let no of books=x   ((3600)/x) −((3600)/(x+6))=50  ⇒((3600(x+6−x))/(x^2 +6x))=50  ⇒72×6=x^2 +6x  ⇒x^2 +6x−72×6=0  ⇒x^2 +(24−18)x−72×6=0  ⇒(x+24)(x−18)=0   x=18

letnoofbooks=x3600x3600x+6=503600(x+6x)x2+6x=5072×6=x2+6xx2+6x72×6=0x2+(2418)x72×6=0(x+24)(x18)=0x=18

Commented by peter frank last updated on 18/Jul/24

thank you

thankyou

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