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Question Number 209672 by Ansu last updated on 18/Jul/24

Answered by som(math1967) last updated on 18/Jul/24

((3x−1)/4)=((9−x)/x) ⇒3x^2 −x=36−4x ⇒3x^2 +3x−36=0 ⇒x^2 +x−12=0 ⇒(x+4)(x−3)=0 x=3

3x−14=9−xx⇒3x2−x=36−4x⇒3x2+3x−36=0⇒x2+x−12=0⇒(x+4)(x−3)=0x=3

Answered by Sutrisno last updated on 18/Jul/24

((ad)/(ab))=((ae)/(ac)) ((3x−1)/(3x+3))=((9−x)/9) ((3x−1)/(x+1))=((9−x)/3) 9x−3=−x^2 +8x+9 x^2 +x−12=0 (x−3)(x+4)=0 x=3

adab=aeac3x−13x+3=9−x93x−1x+1=9−x39x−3=−x2+8x+9x2+x−12=0(x−3)(x+4)=0x=3

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