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Question Number 209847 by SonGoku last updated on 23/Jul/24

Answered by mr W last updated on 23/Jul/24

$$depth=h$$$$h=\sqrt{{23}^2-{\left(\frac{53-41}{2}\right)}^2}=\sqrt{493}=22.20m$$$$crosssectionarea=A$$$$A=\frac{53+41}{2}\times h=1043.57m^2$$$$wettedperimeter=P$$$$P=23+41+23=87m$$$$hydraulicradius=R$$$$R=\frac{A}{P}=\frac{1043.57}{87}=12m$$

Commented by SonGoku last updated on 23/Jul/24

$$\mathrm{Thank}\mathrm{you}!$$

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