Question and Answers Forum

All Questions      Topic List

Arithmetic Questions

Previous in All Question      Next in All Question      

Previous in Arithmetic      Next in Arithmetic      

Question Number 209860 by lmcp1203 last updated on 23/Jul/24

$$$$$$\mathrm{Magnitude}\mathrm{A}\mathrm{varies}\mathrm{proportionally}\mathrm{with}(\mathrm{B}\mathrm{squared}+4)\mathrm{and}\mathrm{magnitude}\mathrm{B}\mathrm{varies}\mathrm{proportionally}\mathrm{with}$$$$\left(t\mathrm{he}\mathrm{root}\mathrm{of}\mathrm{C}\right)-5.\mathrm{Also}\mathrm{when}\mathrm{A}\mathrm{is}16,\mathrm{B}\mathrm{is}12\mathrm{and}\mathrm{C}\mathrm{takes}\mathrm{the}\mathrm{value}81.\mathrm{Calculate}\mathrm{the}\mathrm{value}\mathrm{that}\mathrm{A}\mathrm{takes}$$$$\mathrm{wh}e\mathrm{n}\mathrm{C}\mathrm{is}49.helpme.please.thanks$$

Answered by mr W last updated on 23/Jul/24

$$A=\alpha (B^2-4)$$$$B=\beta (\sqrt{C}-5)$$$$16=\alpha ({12}^2-4)\Rightarrow \alpha =\frac{4}{35}$$$$12=\beta (\sqrt{81}-5)\Rightarrow \beta =3$$$$whenC=49:$$$$B=3\times (\sqrt{49}-5)=6$$$$A=\frac{4}{35}(6^2-4)=\frac{128}{35}\leftarrow answer$$

Answered by lmcp1203 last updated on 23/Jul/24

$$thankyou.$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com