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Question Number 209957 by Jubr last updated on 26/Jul/24

If x, y are contain in natural numbers and x² + y² = 613² Find the values of x + y = ?

Answered by Frix last updated on 27/Jul/24

$${35}^2+{612}^2={613}^{2}x+y=647$$$$0^2+{613}^2={613}^{2}x+y=613$$

Commented by Jubr last updated on 28/Jul/24

$$Thankssir$$

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