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Question Number 209965 by mnjuly1970 last updated on 27/Jul/24

Answered by mr W last updated on 27/Jul/24

Commented by mr W last updated on 27/Jul/24

$$\frac{AD}{DB}=\frac{AD}{FH}=\frac{1}{2}\Rightarrow \frac{AD}{AB}=\frac{1}{3}$$$$\frac{AE}{AC}=\frac{AD}{FG}=\frac{1}{2}$$$$\frac{\mathrm{\Delta }ADE}{\mathrm{\Delta }ABC}=\frac{AE\times AD}{AC\times AB}=\frac{1}{2}\times \frac{1}{3}=\frac{1}{6}$$

Commented by mnjuly1970 last updated on 27/Jul/24

$$thxalotsir$$

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