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Question Number 209986 by a.lgnaoui last updated on 28/Jul/24

Solve    ax^3 −bx(√x) +c=0        (a, b, c)∈R^3     and x∈R  (the value of x for a=1,  b=9,c=8)

Solveax3bxx+c=0(a,b,c)R3andxR(thevalueofxfora=1,b=9,c=8)

Answered by mr W last updated on 28/Jul/24

let t=x(√x)  at^2 −bt+c=0  ⇒t=((b±(√(b^2 −4ac)))/(2a))  ⇒x=t^(2/3) =(((b±(√(b^2 −4ac)))/(2a)))^(2/3)

lett=xxat2bt+c=0t=b±b24ac2ax=t23=(b±b24ac2a)23

Commented by a.lgnaoui last updated on 28/Jul/24

thanks

thanks

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