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Question Number 210014 by Ismoiljon_008 last updated on 28/Jul/24

Commented by Ismoiljon_008 last updated on 28/Jul/24

   Help Please

HelpPlease

Commented by a.lgnaoui last updated on 28/Jul/24

∡FBA=∡FBC?      AB//CD?

FBA=FBC?AB//CD?

Commented by Ismoiljon_008 last updated on 28/Jul/24

   Yes,  ABCD is parallelogram and     BF  is bissector.

Yes,ABCDisparallelogramandBFisbissector.

Answered by A5T last updated on 28/Jul/24

Commented by A5T last updated on 28/Jul/24

Through F, construct a line parallel to AB.  ⇒((AG)/(AD))=((AF)/(AE))=((FG)/(DE))=(1/2)⇒AG=GD=(x/2);FG=2.5  ⇒(x/2)+2.5=10⇒x=15

ThroughF,constructalineparalleltoAB.AGAD=AFAE=FGDE=12AG=GD=x2;FG=2.5x2+2.5=10x=15

Commented by Ismoiljon_008 last updated on 29/Jul/24

thank you very much

thankyouverymuch

Answered by mr W last updated on 28/Jul/24

Commented by mr W last updated on 28/Jul/24

CG=AD=x  EG=AE ⇒FG=3×AF  ((10)/(AF))=((2x)/(FG)) ⇒10=((2x)/3) ⇒x=15

CG=AD=xEG=AEFG=3×AF10AF=2xFG10=2x3x=15

Commented by Ismoiljon_008 last updated on 29/Jul/24

thank you very much

thankyouverymuch

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