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Question Number 210292 by 281981 last updated on 05/Aug/24

Commented by mr W last updated on 05/Aug/24

$$allanswersarewrong!$$

Answered by mr W last updated on 05/Aug/24

$$\frac{x-\alpha }{3}=\frac{y-(2\alpha -1)}{-2}=\frac{-2[3\alpha -2(2\alpha -1)+4]}{3^2+{(-2)}^2}$$$$\Rightarrow 13x=19\alpha -36$$$$\Rightarrow 13y=22\alpha +11$$$$$$$$\Rightarrow 19y-22x=77$$

Commented by mr W last updated on 05/Aug/24

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