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Question Number 210542 by SANOGO last updated on 12/Aug/24

Commented by Rasheed.Sindhi last updated on 12/Aug/24

$$x+y+z=1\Rightarrow {(x+y+z)}^2=1$$

Commented by Frix last updated on 12/Aug/24

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Answered by JuniorKepler last updated on 12/Aug/24

$$since(x+y+z)=1$$$${(x+y+z)}^2=1^2$$$$=1$$

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