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Question Number 210701 by noraell last updated on 17/Aug/24

Answered by Berbere last updated on 18/Aug/24

f′(x)=3x^2 +1≥1 Increase steictly   f is bijection R→R⇒f^−  existe  2f(x)+3f^− (x)=10  since f is increasing ⇒f^−  increase   ⇒2f(x)+3f^− (x)=g(x) increase  f(2)=2⇒f^− (2)=2  2.f(2)+3f^− (2)=10=g(2)  since g increase x=2 is unique solution  of 2f(x)+3f^− (x)=10

f(x)=3x2+11IncreasesteictlyfisbijectionRRfexiste2f(x)+3f(x)=10sincefisincreasingfincrease2f(x)+3f(x)=g(x)increasef(2)=2f(2)=22.f(2)+3f(2)=10=g(2)sincegincreasex=2isuniquesolutionof2f(x)+3f(x)=10

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