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Question Number 210701 by noraell last updated on 17/Aug/24
Answered by Berbere last updated on 18/Aug/24
f′(x)=3x2+1⩾1IncreasesteictlyfisbijectionR→R⇒f−existe2f(x)+3f−(x)=10sincefisincreasing⇒f−increase⇒2f(x)+3f−(x)=g(x)increasef(2)=2⇒f−(2)=22.f(2)+3f−(2)=10=g(2)sincegincreasex=2isuniquesolutionof2f(x)+3f−(x)=10
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