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Question Number 210906 by hardmath last updated on 21/Aug/24
19x−x2x+1⋅(x+19−xx+1)=78find:x=?
Answered by Frix last updated on 21/Aug/24
Reconstructingyourequation:x=a2±a2−4b2∨x=b2±4a−b22i(∗)(x2−ax+b)(x2−bx+a)=0(x2−ax+b)(x2−bx+a)−ab(x+1)2=−ab(x+1)2x(x−(a+b))(x2+(a+b))=−ab(x+1)2x((a+b)−x)(x2+(a+b))(x+1)2=ab(a+b)x−x2x+1×x2+(a+b)x+1=ab(a+b)x−x2x+1×(x+(a+b)−xx+1)=aba=13∧b=619x−x2x+1×(x+19−xx+1)=78(∗)x=132±1452∨x=3±2i
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