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Question Number 210918 by VICHET last updated on 22/Aug/24
Answered by Frix last updated on 22/Aug/24
Letx=t+11limt→0−∣x∣x=limt→0−−xx=−1limt→0+∣x∣x=limt→0+xx=1⇒Limitdoesnotexist
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