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Question Number 210948 by cherokeesay last updated on 23/Aug/24

Commented by cherokeesay last updated on 23/Aug/24

If only the result is accompanied by a  diagam it will be perfect.  thanks.

Ifonlytheresultisaccompaniedbyadiagamitwillbeperfect.thanks.

Answered by A5T last updated on 23/Aug/24

Let [BEC]=4y⇒[CED]=8y=?  (([ABE])/([BED]=[BEC]+[CED]))=((36−4y)/(12y))=(8/3)⇒y=1  ⇒?=8y=8  ((11×12sin∠ADB)/2)=36+8=44⇒sin∠ADB=(2/3)  ⇒cos∠ADB=((√5)/3)  x^2 =11^2 +12^2 −2×11×4(√5)⇒x=(√(265−88(√5)))

Let[BEC]=4y[CED]=8y=?[ABE][BED]=[BEC]+[CED]=364y12y=83y=1?=8y=811×12sinADB2=36+8=44sinADB=23cosADB=53x2=112+1222×11×45x=265885

Commented by A5T last updated on 23/Aug/24

Commented by cherokeesay last updated on 23/Aug/24

thank you so much !

thankyousomuch!

Answered by mr W last updated on 23/Aug/24

Commented by mr W last updated on 23/Aug/24

(?/(?+36))=((8×3)/((8+4)×(3+8))) ⇒?=8  (((4+8)h)/2)=36+8 ⇒h=((22)/3)  FD=(√((8+3)^2 −(((22)/3))^2 ))=((11(√5))/3)  BC=12−((11(√5))/3)  x=(√((12−((11(√5))/3))^2 +(((22)/3))^2 ))     =(√(265−88(√5)))≈8.26

??+36=8×3(8+4)×(3+8)?=8(4+8)h2=36+8h=223FD=(8+3)2(223)2=1153BC=121153x=(121153)2+(223)2=2658858.26

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