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Question Number 210972 by ujah last updated on 25/Aug/24

Answered by TonyCWX08 last updated on 25/Aug/24

$$a.$$$$n\left(Conly\right)=18-6-3=9$$$$$$$$b.$$$$n\left(Onesubjectonly\right)$$$$=n\left(Conly\right)+n\left(Ponly\right)+n\left(Monly\right)$$$$=9+5+(22-6-2)$$$$=14+14$$$$=28$$$$$$$$c.$$$$n\left(Twosubjectonly\right)$$$$=3+2$$$$=5$$

Commented by TonyCWX08 last updated on 25/Aug/24

Answered by mm1342 last updated on 25/Aug/24

$$32-16=16$$$$\Rightarrow x+y+z=16\mathrm{\&}z+y=9\mathrm{\&}y+x=14$$$$\Rightarrow x=7\mathrm{\&}y=7\mathrm{\&}z=2$$$$\Rightarrow ans$$$$\left(a\right):2\left(b\right):14\left(c\right):12$$$$$$

Commented by mm1342 last updated on 25/Aug/24

Commented by TonyCWX08 last updated on 25/Aug/24

$$okay$$

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