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Question Number 211020 by peter frank last updated on 26/Aug/24

Answered by mahdipoor last updated on 26/Aug/24

$$dV=\left(\pi y^2\right)\left(dx\right)=\pi \frac{{(x-a)}^2{(x-b)}^2}{c^2}dx$$$$V=\int dV=\frac{\pi }{c^2}{\int }_a^b{(x-a)}^2{(x-b)}^{2}dx$$$$=\frac{\pi }{c^2}{[\frac{{(x-a)}^3{(x-b)}^2}{3}-\frac{{(x-a)}^4(x-b)}{6}-\frac{{(x-b)}^5}{30}]}_a^b=$$$$\frac{\pi {(a-b)}^5}{30}$$

Commented by peter frank last updated on 27/Aug/24

$$\mathrm{thank}\mathrm{you}\mathrm{mahdipoor}$$

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