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Question Number 211075 by ajfour last updated on 27/Aug/24

sin (θ+φ)=θ  sin θ=φ  find θ and φ.

sin(θ+ϕ)=θsinθ=ϕfindθandϕ.

Answered by Ghisom last updated on 27/Aug/24

we can only approximate  φ=sin θ  sin (θ+sin θ) =θ  1. θ=φ=0  2. θ≈±.973696169714∧φ≈±.826969516935

wecanonlyapproximateϕ=sinθsin(θ+sinθ)=θ1.θ=ϕ=02.θ±.973696169714ϕ±.826969516935

Answered by ajfour last updated on 27/Aug/24

cos (θ+φ)=(√(1−θ^2 ))  tan (θ+φ)=(θ/( (√(1−θ^2 ))))  ((tan θ+tan φ)/(1−tan θtan φ))=(θ/( (√(1−θ^2 ))))  tan φ=((θ−(√(1−θ^2 ))tan θ)/( (√(1−θ^2 ))+θtan θ))  ...yes so b it

cos(θ+ϕ)=1θ2tan(θ+ϕ)=θ1θ2tanθ+tanϕ1tanθtanϕ=θ1θ2tanϕ=θ1θ2tanθ1θ2+θtanθ...yessobit

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