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Question Number 211402 by efronzo1 last updated on 08/Sep/24
Answered by A5T last updated on 08/Sep/24
Q211029,wecanfindapolynomialf(x)f(x)=xn+−1f(3)=28⇒f(x)=x3+1(x3+1)(1x3+1)=(x3+1)+(1x3+1)⇒f(−2)+f(−12)=−(618)=−498
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