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Question Number 211492 by swargiya last updated on 11/Sep/24

Answered by BHOOPENDRA last updated on 11/Sep/24

$${sin}^{-1}x-(\frac{\pi }{2}-{sin}^{-1}x)=\frac{\pi }{6}$$$$2{sin}^{-1}x=\frac{\pi }{6}+\frac{\pi }{2}$$$${sin}^{-1}x=\frac{\pi }{3}$$$$x=sin\left(\frac{\pi }{3}\right)=\frac{\sqrt{3}}{2}$$

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