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Question Number 211513 by Davidtim last updated on 11/Sep/24

$$whyweuseAmpiermetersequence$$$$withresistanceincircuit?$$

Commented by Frix last updated on 11/Sep/24

$$\mathrm{Because}$$$$\mathrm{Ohm}=\frac{\mathrm{Volt}}{\mathrm{Ampere}}$$$$\iff$$$$\mathrm{Volt}=\mathrm{Ampere}\times \mathrm{Ohm}$$$$\iff$$$$\mathrm{Ampere}=\frac{\mathrm{Volt}}{\mathrm{Ohm}}$$$$\mathrm{If}\mathrm{you}\mathrm{have}\mathrm{low}\mathrm{to}\mathrm{no}\mathrm{resistance}\mathrm{the}\mathrm{current}$$$$\mathrm{becomes}\mathrm{very}\mathrm{high}\mathrm{and}{\mathrm{you}}^{\prime }\mathrm{ll}\mathrm{end}\mathrm{with}\mathrm{an}$$$$\mathrm{electrical}\mathrm{short}.\mathrm{Your}\mathrm{meter}\mathrm{will}\mathrm{blow}.$$

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