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Question Number 211575 by BaliramKumar last updated on 13/Sep/24

Answered by som(math1967) last updated on 13/Sep/24

 (a)(1/2)(m+n+(1/m)+(1/n))

(a)12(m+n+1m+1n)

Answered by A5T last updated on 13/Sep/24

sec^2 θ−tan^2 θ=(secθ−tanθ)(secθ+tanθ)=1  ⇒secθ+tanθ=(1/n)  cosec^2 θ−cot^2 θ=(cosecθ−cotθ)(cosecθ+cotθ)=1  ⇒cosecθ+cotθ=(1/m)  ⇒(1/2)(m+n+(1/m)+(1/n))=cosecθ+secθ⇒(a)

sec2θtan2θ=(secθtanθ)(secθ+tanθ)=1secθ+tanθ=1ncosec2θcot2θ=(cosecθcotθ)(cosecθ+cotθ)=1cosecθ+cotθ=1m12(m+n+1m+1n)=cosecθ+secθ(a)

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