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Question Number 211575 by BaliramKumar last updated on 13/Sep/24
Answered by som(math1967) last updated on 13/Sep/24
(a)12(m+n+1m+1n)
Answered by A5T last updated on 13/Sep/24
sec2θ−tan2θ=(secθ−tanθ)(secθ+tanθ)=1⇒secθ+tanθ=1ncosec2θ−cot2θ=(cosecθ−cotθ)(cosecθ+cotθ)=1⇒cosecθ+cotθ=1m⇒12(m+n+1m+1n)=cosecθ+secθ⇒(a)
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