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Question Number 211632 by sonukgindia last updated on 15/Sep/24
Answered by A5T last updated on 15/Sep/24
ϕ(1000)=40020242024≡0(mod16);20242024≡1(mod25)⇒20242024=25q+1≡(0mod16)⇒q≡7(mod16)⇒20242024=25(16k+7)+1=400k+176≡176(mod400)⇒202420242024≡24176(mod1000)≡(2411)16≡2416≡2411×245≡246≡976(mod1000)⇒?=976
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