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Question Number 211634 by BaliramKumar last updated on 15/Sep/24

Answered by golsendro last updated on 15/Sep/24

$${\mathrm{x}}^3+\frac{1}{{\mathrm{x}}^3}=\frac{64+1}{8}=2^3+\frac{1}{2^3}$$$${\mathrm{y}}^3+\frac{1}{{\mathrm{y}}^3}=\frac{729+1}{27}=3^3+\frac{1}{3^3}$$$$\mathrm{xy}=6$$

Commented by BaliramKumar last updated on 15/Sep/24

$$thanks$$

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